Archived posting to the Leica Users Group, 2008/04/27

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Subject: [Leica] How many M8s new list 13
From: mark at rabinergroup.com (Mark Rabiner)
Date: Sun Apr 27 22:24:26 2008

> 52 LUGGERS and 58 M8s now.
> 
> 
> Adam Bridge,
> Barney
> Benjamin Marks
> Bernardo Feio
> Bob Adler
> Brian our barkeep!
> Charles Hehl
> Chris Williams
> Claudio Rimediotti
> Clive Moss
> Craig Semetko
> Don Dory
> Ed Albesi
> Eric Calderwood
> Felix
> Frank Dernie
> Gene Duprey
> Geoff,
> George Lottermoser,
> H?kan Dennersten
> Haya Alkhalifa
> Henning (x2)
> Howard Cummer (x2)
> Howard Ritter
> Hugh Thompson
> Jeffery Smith
> Jeff Moore (x2)
> John Nebel
> Ken Iisaka
> Lee Hermann
> Len (x2),
> Leo Wesson
> Lucien
> Marty (x2)
> Matthew Hunt
> Mehrdad
> Neil Friedenthal
> Neil Miller
> Peter,
> Rei
> Richard Clompus
> Robert Baron
> Sam Kennard
> Sonny,
> Steve Barbour,
> Steve Unsworth,
> Tarek Charara
> Ted,
> Tina (x2),
> Vick Ko
> Wade
> Will Larsen
> 
> 
58 Sluggers! I thought I read.

Wiki says:
Fifty-eight is the seventeenth discrete bi-prime and the ninth in the (2.q)
family. With 57 it forms the fourth discrete bi-prime pair. 58 has an
aliquot sum of 32 and is the second composite member of the 31-aliquot tree.
Fifty-eight is the sum of the first seven prime numbers, an 11-gonal number,
and a Smith number. Given 58, the Mertens function returns 0.
There is no answer to the equation x - ?(x) = 58, making 58 a noncototient.
However, the sum of the totient function for the first thirteen integers is
58.

The number of counties in California
The minimum wind speed needed to issue a Severe Thunderstorm Warning.

Mark William Rabiner
markrabiner.com




In reply to: Message from len-1 at comcast.net (Leonard Taupier) ([Leica] How many M8s new list 13)