Archived posting to the Leica Users Group, 2008/04/27
[Author Prev] [Author Next] [Thread Prev] [Thread Next] [Author Index] [Topic Index] [Home] [Search]> 52 LUGGERS and 58 M8s now. > > > Adam Bridge, > Barney > Benjamin Marks > Bernardo Feio > Bob Adler > Brian our barkeep! > Charles Hehl > Chris Williams > Claudio Rimediotti > Clive Moss > Craig Semetko > Don Dory > Ed Albesi > Eric Calderwood > Felix > Frank Dernie > Gene Duprey > Geoff, > George Lottermoser, > H?kan Dennersten > Haya Alkhalifa > Henning (x2) > Howard Cummer (x2) > Howard Ritter > Hugh Thompson > Jeffery Smith > Jeff Moore (x2) > John Nebel > Ken Iisaka > Lee Hermann > Len (x2), > Leo Wesson > Lucien > Marty (x2) > Matthew Hunt > Mehrdad > Neil Friedenthal > Neil Miller > Peter, > Rei > Richard Clompus > Robert Baron > Sam Kennard > Sonny, > Steve Barbour, > Steve Unsworth, > Tarek Charara > Ted, > Tina (x2), > Vick Ko > Wade > Will Larsen > > 58 Sluggers! I thought I read. Wiki says: Fifty-eight is the seventeenth discrete bi-prime and the ninth in the (2.q) family. With 57 it forms the fourth discrete bi-prime pair. 58 has an aliquot sum of 32 and is the second composite member of the 31-aliquot tree. Fifty-eight is the sum of the first seven prime numbers, an 11-gonal number, and a Smith number. Given 58, the Mertens function returns 0. There is no answer to the equation x - ?(x) = 58, making 58 a noncototient. However, the sum of the totient function for the first thirteen integers is 58. The number of counties in California The minimum wind speed needed to issue a Severe Thunderstorm Warning. Mark William Rabiner markrabiner.com