Archived posting to the Leica Users Group, 2008/05/10

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Subject: [Leica] Leica R-10 at Photokina 2008
From: pjleeson at mchsi.com (Philip Leeson)
Date: Sat May 10 17:08:51 2008
References: <050820081740.6597.48233B270008C969000019C5219791299503010CD2079C080C03BF970A9D9F9A0B9D09@mchsi.com> <00f601c8b133$ca9f11d0$6101a8c0@jimnichols> <20080510162215.GU18271@jbm.org>

Seems so obvious now that I think about it.
Should've paid more attention in Geometry...

Phil
On May 10, 2008, at 11:22 AM, Jeff Moore wrote:

> 2008-05-08-13:48:57 Jim Nichols:
>> I agree with Gene.  If a lens will cover 36mm in width, it will  
>> cover the
>> same dimension in height. Hence, it should cover at least 36x36mm.
>
> Er, what part of the Pythagorean theorem is confusing here?  Don't  
> just
> count on words which sound nice together; draw the two formats packed
> into circles, with the enclosing circles just kissing the corners of  
> the
> enclosed rectangle (which might be a square).  If an image circle is  
> to
> be guaranteed to cover a rectangular format, the circle's diameter  
> must
> be greater than or equal to the format's diagonal. The format's  
> diagonal
> is the square root of the squares of the sides.
>
>  http://en.wikipedia.org/wiki/Pythagorean_theorem
>
> For 24x36mm, that's 43.3mm (hence the Leica MTF graphs which go from
> zero to 21.6mm, half that -- the radius from center to edge of the  
> image
> circle which covers 24x36).
>
> For 36x36mm that's 50.9mm.
>
> 50.9 is bigger than 43.3.
>
> Sure, some current R lenses (especially the longer ones) may have
> coverage to spare, but more coverage *would* be required.
>
> -Jeff
>
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In reply to: Message from grduprey at mchsi.com (grduprey@mchsi.com) ([Leica] Leica R-10 at Photokina 2008)
Message from jhnichols at bellsouth.net (Jim Nichols) ([Leica] Leica R-10 at Photokina 2008)
Message from jbm at jbm.org (Jeff Moore) ([Leica] Leica R-10 at Photokina 2008)