Archived posting to the Leica Users Group, 2010/09/04
[Author Prev] [Author Next] [Thread Prev] [Thread Next] [Author Index] [Topic Index] [Home] [Search]it feels like years since the last filter kerfuffle. as for myself, in 2007 i swapped heliopan UV-MRC Slims for leica UV-IRs and in 2009 i switched back. -rei On 09/04/2010 02:52 AM, Henning Wulff wrote: > At 9:45 AM +1000 9/4/10, Geoff Hopkinson wrote: > >> Why do you think that the filters would likely shatter into a million >> ultra >> sharp pieces? Good ones at least are laminated materials. >> > > At present only polarizers are still sometimes laminated; most others > are dyed in the mass. The latter would shatter. > > In earlier times coloured filters were laminated because the dyes > could be controlled better in gel form than as dyes added to molten > glass. They were abandoned when dyed in the mass became possible > because the gels tended to fade relatively quickly, and they > necessitated thicker filters which caused a lot of plano-parallelism > problems. I once (in the 70's) checked about 50 filters; over 75% of > the laminated gel types had surfaces that weren't perfectly parallel > which would cause serious problems with some lenses. The gels also > didn't really provide any structural strength; not like the vinyl in > laminated safety glass. > > As far as the UV filter argument goes, the filter ring ding vs. lens > rim ding I can understand, but my lens shades do an even better job > and they shade besides. Also, if you shatter the filter after whacking > the lens against something, it does not necessarily follow that the > front element would have been damaged if the filter had not been > there. Maybe yes, maybe no. > > As you might guess from the above, I use filters when there is a good > reason, but leave it off otherwise. I did some tests once which showed > that under some circumstances the images gets slightly degraded when a > filter is used. Not often, but still... > > If you use a filter, make sure the coatings are good. It doesn't have > to be the most expensive one. >