Archived posting to the Leica Users Group, 2006/01/16

[Author Prev] [Author Next] [Thread Prev] [Thread Next] [Author Index] [Topic Index] [Home] [Search]

Subject: [Leica] OT: EV to lux conversion
From: philippe.orlent at pandora.be (Philippe Orlent)
Date: Mon Jan 16 14:28:17 2006
References: <26BBFBBB-0032-45F6-B6BB-6011520DF287@bradbrad.com>

between 11 and 12. I think :-)



Op 16-jan-06, om 23:07 heeft brad daly het volgende geschreven:

> esteemed optical knowledgees,
>
> i need to know how to convert EV readings to lux.  i have found the  
> formula
>
> lux = 2.5 x 2^EV
>
> siting here at my desk, i have an EV reading of 8, so
>
> lux = 2.5 x 2^8
>
> or
>
> lux = 640
>
> what i really need to know is this, if the original formula is  
> indeed the correct one.  that is, i need to be able to solve for x  
> in this equation:
>
> 10,000 lux = 2.5 x 2^x
>
> i need to know what EV reading equals 10,000 lux.
>
> the problem is that i can't remember how to solve for x as an  
> exponent.  fairly simple math, i realize, but something i've  
> completely forgotten how to do.
>
>
>
> --
> brad daly
> brad@bradbrad.com
> http://www.bradbrad.com
>
> What Would Bill Hicks Say?
>
> All photographs are accurate. None of them is the truth.
>     --Richard Avedon
>
>
> _______________________________________________
> Leica Users Group.
> See http://leica-users.org/mailman/listinfo/lug for more information
>


Replies: Reply from brad at bradbrad.com (brad daly) ([Leica] OT: EV to lux conversion)
Reply from red735i at earthlink.net (Frank Filippone) ([Leica] OT: EV to lux conversion)
In reply to: Message from brad at bradbrad.com (brad daly) ([Leica] OT: EV to lux conversion)