Archived posting to the Leica Users Group, 2001/10/31

[Author Prev] [Author Next] [Thread Prev] [Thread Next] [Author Index] [Topic Index] [Home] [Search]

Subject: Re: [Leica] Is M6TTL selective metering really 2/3 of the short side of the frame?
From: John Collier <jbcollier@powersurfr.com>
Date: Wed, 31 Oct 2001 07:16:21 -0700

This seeming contradiction disappears when you remember that the framelines
only show 93% of the area of the film at closest focus. At infinity the
framelines show even less of the film area (depending on the focal length of
the lens).

John Collier 

> From: Ray Moth <ray_moth@yahoo.com>
> 
> I am confused by Leica's statement, in my M6 TTL manual, that the
> diameter of the selective metering area is 2/3 the length of the short
> side of the frame. Since the white spot on the first curtain is 12mm
> diameter and the short side of the frame is 24mm, how can it be 2/3?
> Seems more like 1/2 to me. Am I right or am I just dumb? (Leica also
> says the selective area is 13% of the frame area, with which I agree).
> 

- --
To unsubscribe, see http://mejac.palo-alto.ca.us/leica-users/unsub.html

Replies: Reply from Mark Rabiner <mark@rabiner.cncoffice.com> (Re: [Leica] Is M6TTL selective metering really 2/3 of the shortside of the frame?)