[Leica] lightroom question....

[Robert Baron]

Thanks!  This may save me $9.95 a month, but I'll have to cancel one of the
contracts and then reinstall CC on that computer I suppose. And  I
certainly don't think today is a good day to call Adobe!  ;-)

On Tue, Apr 21, 2015 at 7:10 PM, John McMaster <john at mcmaster.co.nz> wrote:

> On a Mac (assume same for PC):
>
> Go to CC 'infinity' logo on toolbar > Arrow at top right > Preferences >
> General > Sign Out. That is all, then sign in when needed again. I found
> after I had logged on to two machines that when I was at my third it
> allowed me to remotely log the other two out...
>
> john
>
> -----Original Message-----
>
> I feel a headache coming on.
>
> I've been paying for two separate subscriptions; one covers my iMac at
> home and my MacBookAir laptop and the other covers my Windows desktop at my
> office.  I obviously can't be using both the office Windows desktop and the
> iMac at home simultaneously, since they are about 15 miles apart.
>
> A simple first question:  What does 'logging out' and 'logging in' entail?
> That's not the same thing as deactivating, is it?
>
> A second question:  What are the odds Adobe tech support can help me solve
> this issue?
>
> --Bob
>
>
> On Tue, Apr 21, 2015 at 6:54 PM, John McMaster <john at mcmaster.co.nz>
> wrote:
>
> > Two is the concurrent limit, but you can log out of one then log in on
> > a third as long as only two are live at the same time...
> >
> > john
> >
> > -----Original Message-----
> >
> > ===On Tue, Apr 21, 2015 at 4:16 PM, Sonny Carter <sonc.hegr at gmail.com>
> > wrote:
> >
> > >
> > >
> > > I didn't think I wanted to be a subscriber, but broke down and gave
> > > it a try.  The convenience of not having to keep up with update for
> > > three computers is terrific.
> >
> >
> > Do you have one $9.95/month subscription covering 3 computers?  I was
> > told by an Adobe salesperson that I could only use a subscription on 2
> > computers and I would have to buy a second subscription for a third
> computer.
> >
> > --Bob
> >
>
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