Archived posting to the Leica Users Group, 2010/01/28
[Author Prev] [Author Next] [Thread Prev] [Thread Next] [Author Index] [Topic Index] [Home] [Search]Le 28 janv. 10 ? 12:50, Seth Rosner a ?crit : > > Daniel Tan queried: > > > > "How does one measure 0.08s?" > > > > answer: with a hand-held chronograph, preferably a Rolex Submariner, > held in > the hand that is not activating the Leica M9 shutter. ;-) > > > > best I could do at 6:37AM > > You can also measure 0.008s and multiply by 10, easy ! Ok, I'll go back to bed too now. Phx > > Seth > > > _______________________________________________ > Leica Users Group. > See http://leica-users.org/mailman/listinfo/lug for more information > NO ARCHIVE