Archived posting to the Leica Users Group, 2009/09/05

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Subject: [Leica] math challenged
From: mark at rabinergroup.com (Mark Rabiner)
Date: Sat, 05 Sep 2009 19:03:09 -0400

> OK, so I just learned that the M8's have a 0.68 VF. My question is, what 
> does
> that translate into, relative to the crop factor of that sensor?  In other
> words, is it like what an approximately 0.45 VF would show you on a FF 
> camera?
> 
> Since 0.72 has been the 'standard' VF since the M2, I'd have figured that 
> in
> the M8 they would want to reproduce the same relative field of view, lens 
> for
> lens, narrowing it appropriately.
> 
> If I'd've bothered to wonder about it I would have figured the M8 VF to be
> 0.86, or 0.91 like the M3 - something narrower than 0.72.
> 
> The 0.68 field of view VF in the M8 must REALLY favor the wides, taking in 
> a
> much broader field of view than would the 0.58 VF with the same lens on a 
> full
> frame camera.
> 
> 
It was the .58 which favored the wides
.85 which favored the telles and
.63 the long time norm with the  late 90's M's.
>From what I recall.


Mark William Rabiner





In reply to: Message from h_arche at yahoo.com (H. Ball Arche) ([Leica] math challenged)