Archived posting to the Leica Users Group, 2001/03/18
[Author Prev] [Author Next] [Thread Prev] [Thread Next] [Author Index] [Topic Index] [Home] [Search]Thank you, Steve! It is a interesting article, indeed. I made some math for myself, maybe someone will find it interesting: 1. One "digital pixel" is made from at least 3 pixels, usually 4 (R+G+B+additional gray). 2. Typical film, exposed by typical advanced photographer, exhibits at least 80 lpmm. 3. At 24x36 mm our young photographer can record 24x80 = 2000 points vertically and 36x80 = 3000 points horizontally, giving average 6 000 000 points. 4. To record image with similar resolution, digital camera needs 4 x 6 000 000 = 24 000 000 pixels. So we need a 24 megapixel monster. 5. To store that image in 32 bit color (True Color), we need 6 000 000 x 4 (there is 8 bits in byte) , e.g. 24 MB. 6. Assuming we are using JPEG compression and image has an average level of detail, we still need about 6-8 megabytes per image. Not enough? Now let's try other example: A.) My Summitar (at f/5.6) photos needs 6000x4000 pixels scans to at least average number of details and tonality from my original photo (on APX 100). It gives about 100 MB image, about 24 MB JPEG compressed. B.) My Rodenstock MF photos needs at least 8000x10000 pixels scan do record all details from film. Typical scan is about 400 MB. Or 150 MB JPEG compressed. Where to store it? How should I act when my baterries dry out? How will moisture affect my camera operation? How should I make photos in Winter, at -10 - -20 degrees Celsius? Yours very sceptical - ------------------- St. - ----------------------------------------------- FREE! The World's Best Email Address @email.com Reserve your name now at http://www.email.com