Archived posting to the Leica Users Group, 2010/03/01
[Author Prev] [Author Next] [Thread Prev] [Thread Next] [Author Index] [Topic Index] [Home] [Search]George, You are right to point out the fact that on most serious cameras the pixel size is somewhere between 5 and 10 microns. There is a physical explanation to this. ZVisible light wavelength is spread between (roughly) 0.4 and 0.7 microns. Lenses do have both geometrical optical aberrations and diffraction that limit their resolution. Again in very rough terms, geometrical aberrations are greater at large apertures, inversely proportional to the inverse of the f-number. Technology may help reduce them (better glass with higher refractive indexes and less dispersion, more complex designs, aspheric elements etc.) to a certain extent - we all know Leica are very good at this. On the other hand, diffraction can't be avoided, it is a physical law. Parallel light coming through a hole (here, the diaphragm) in a "perfect" lens will draw on the film or sensor, not a single point as we woulod like it, but a "diffraction pattern" that looks a bit like the circles when one drops a stone into a lake. The main spot, the central diffraction pattern has a diameter equal to 1.22*f*lambda/d where f is the focal length, lambda the wavelength and d the diaphragm diameter. As the f-number "n" equals f/d, the diffraction diameter is 1.22*n*lambda. As lambda is not a single value but is spread between 0.4 and 0.7 microns, the diffraction pattern is really ugly with colour fringes on its sides and the effects of diffraction are still visible and annoying inside a circle with diameter approx. 2*n*lambda. As lambda is around 0.5 microns, this means the diffraction pattern diameter will be about 2 microns at f:2l; 4 microns at f:4, etc. As the actual blur pattern is the addition of the effects of diffraction to those of geometrical aberrations, and as it is very expensive to correct geometrical aberrations,in most lenses the blur diameter is a convex (parabola-like) curve with its minimum (= best sharpness) a couple of f-stops above full aperture- the good old Nikon 1.4/50 had its optimum at the centre of the image, at about f:5.6. Top lenses like the recent Leica ones have their optimum very close to full aperture (and this is at a cost!). All in all, one can safely say that the best blur circle diameter of a given lens, measured in microns/micrometers, is equal to about twice its maximum aperture. This is why with a top-of-the-range lens with aperture 2.8 it is wise to choose a pixel size around 6 microns. Quid erat demonstrandum :-) By the way, some P&S cameras are sold as 12 Megapix. Their sensors are often about 4.5 x 6 mm large . This means the pixel size is 1.5 microns, which is totally ridiculous - even worse since most of them use high-factor zooms that go with even more aberrations and low maximum aperture. Actually there can't be more than 0.7 MPix useful in these cameras! All the rest is just redundent data. On the other hand, a pocket camera like the D-lux 4 uses a lens with a very small zoom factor (hence low aberrations) , a high max aperture (hence low diffraction) and ... I don't remember its sensor size but here advertising 10 MPix looks like it makes sense. If I had to draw a conclusion, it is that what matters most of all is the sensor size. Megapixels don't mean anything if the sensor is too small. Jean